Notices
964 Forum 1989-1994
Sponsored by:
Sponsored by:

flywheel sensor

Thread Tools
 
Search this Thread
 
Old Jan 21, 2007 | 02:02 PM
  #136  
Lorenfb's Avatar
Lorenfb
Race Car
20 Year Member
 
Joined: May 2003
Posts: 4,223
Likes: 102
From: SoCal
Default

"It is easy to demonstrate with an aftermarket ECU and a timing light."

Right, some aftermarket ECUs may use an edge triggered approach but NOT the Bosch DME.

You obviously have not tested the 964 DME and don't understand how it functions, but have guessed
about how it must function. There are NO edges to trigger on, i.e. all the "edges" are the same. You need to get a better scope.

Bottomline: You're guessing again! Get a better scope so you can "see" really what's happening.

Note: If the wires (47 & 48) are reversed, the signal is the SAME, i.e. each tooth generates
the same signal no matter what the polarity of the wires.

Last edited by Lorenfb; Jan 21, 2007 at 02:18 PM.
Reply
Old Jan 21, 2007 | 02:07 PM
  #137  
Red rooster's Avatar
Red rooster
Three Wheelin'
 
Joined: Dec 2004
Posts: 1,779
Likes: 1
From: Halifax, Nova Scotia , Canada
Default

Dave,
Sorry for the delay. Had to go to Walmart !

DME pin 1 / Module pin 5 should be a horizontal straight line trace with just the ignition on .

When you crank that signal should be the same horiz. straight line with square pulses going upwards. The width of the pulse should be much less than the gap between pulses.

___I---I______________________I---I_________ etc.

Thats about as close as I can get to give you the idea . Make sure that probe ground is connected to the car ground - battery -ve or a bunch of brown wires bolted to the body .

How does that look ?

Geoff
Reply
Old Jan 21, 2007 | 02:07 PM
  #138  
Geoffrey's Avatar
Geoffrey
Nordschleife Master
20 Year Member
 
Joined: Dec 2001
Posts: 8,305
Likes: 16
From: Kingston, NY
Default

I think my $4000 Tektronics scope works just fine.
Reply
Old Jan 21, 2007 | 02:15 PM
  #139  
Lorenfb's Avatar
Lorenfb
Race Car
20 Year Member
 
Joined: May 2003
Posts: 4,223
Likes: 102
From: SoCal
Default

"I think my $4000 Tektronics scope works just fine."

Not based on the waveform posted. Dave's scope has a MUCH better image of the true signal.
Reply
Old Jan 21, 2007 | 02:16 PM
  #140  
Red rooster's Avatar
Red rooster
Three Wheelin'
 
Joined: Dec 2004
Posts: 1,779
Likes: 1
From: Halifax, Nova Scotia , Canada
Default

Loren/Geoffrey ,
I think you are both right ! The sine wave crank sensor signal is passed through a level comparator where it is converted into 5v amplitude "square "
pulses with edges generated for counting etc.
The input comparator has a level of hysteresis for input signal noise suppresion. Hence the requirement for the signal to be above a certain amplitude .
On my motor simulator I tried reversing the input wave form before switch on ,while monitoring ignition timing etc. There was a hesitation while the system readjusted and then values reverted to the expected.

All the best

Geoff
Reply
Old Jan 21, 2007 | 02:22 PM
  #141  
Lorenfb's Avatar
Lorenfb
Race Car
20 Year Member
 
Joined: May 2003
Posts: 4,223
Likes: 102
From: SoCal
Default

"The sine wave crank sensor signal is passed through a level comparator"

Correct!

"On my motor simulator I tried reversing the input wave form before switch on ,while monitoring ignition timing etc. There was a hesitation while the system readjusted and then values reverted to the expected."

Correct again! Thus the polarity doesn't matter and it's NOT edge triggered, but only "looks" for the
missing tooth.

"Hence the requirement for the signal to be above a certain amplitude ."

Correct again! Thus, the missing tooth provides a reduced amplitude.
Reply
Old Jan 21, 2007 | 02:35 PM
  #142  
Red rooster's Avatar
Red rooster
Three Wheelin'
 
Joined: Dec 2004
Posts: 1,779
Likes: 1
From: Halifax, Nova Scotia , Canada
Default

Loren,
The conversion of sine to square wave does imply edge triggering by eliminating sine wave amplitude from the equation.
If I move the missing teeth position ,the DME timing moves with it . No different to moving the flywheel on the crank .
Therefore the input edge after the missing teeth is a time reference for DME calculations .

Anyway , back to Davids no start !!

All the best


Geoff
Reply
Old Jan 21, 2007 | 03:01 PM
  #143  
Lorenfb's Avatar
Lorenfb
Race Car
20 Year Member
 
Joined: May 2003
Posts: 4,223
Likes: 102
From: SoCal
Default

"When you crank that signal should be the same horiz. straight line with square pulses going upwards. The width of the pulse should be much less than the gap between pulses."

Dont' guess. The ignition pulse is 0/5 volts whose pulse width varies with the desired dwell time
set by the microprocessor and NOT the tooth gap.

"The conversion of sine to square wave does imply edge triggering by eliminating sine wave amplitude from the equation."

No it doesn't! Edge triggering implies that the edge defines relative timing phase/position.
The DME doesn't sense ANY edge, just a tooth (a pulse/zero crossing). The comparator
just looks for "zero crossing" (the pulse) above a reference voltage which allows for discrimination
of the missing tooth. The rate of the pulses (teeth) and NOT any edge determines the RPMs
and the missing tooth (NO edge) determines the TDC point.

"Therefore the input edge after the missing teeth is a time reference for DME calculations ."

It's NOT the edge, but the pulse.

Come on, now you're guesssing too!
Reply
Old Jan 21, 2007 | 03:20 PM
  #144  
david@st ives's Avatar
david@st ives
Thread Starter
Racer
 
Joined: Apr 2004
Posts: 269
Likes: 1
From: Hayle cornwall
Default

Geoff

I have packed away for the evening now, I have no lighting in the garage and my battery is flat again apart from that its freezing out there.

I will try again tommorrow about 4.00 pm uk time.

I am sure i have had that trace on my scope on pin 1, the other trace i described is with the var /volts turned more or less to max.

Dave
Reply
Old Jan 21, 2007 | 03:25 PM
  #145  
david@st ives's Avatar
david@st ives
Thread Starter
Racer
 
Joined: Apr 2004
Posts: 269
Likes: 1
From: Hayle cornwall
Default

"Dont' guess. The ignition pulse is 0/5 volts whose pulse width varies with the desired dwell time
set by the microprocessor and NOT the tooth gap."

I take it the pulse is 0.5 volts is that half a volt.

If so i have got that voltage reading
Reply
Old Jan 21, 2007 | 04:31 PM
  #146  
Red rooster's Avatar
Red rooster
Three Wheelin'
 
Joined: Dec 2004
Posts: 1,779
Likes: 1
From: Halifax, Nova Scotia , Canada
Default

David,
No , the pulse is 0 volts to 5 volts - 5 volts high .

Catch you tomorrow.

Geoff
Reply
Old Jan 21, 2007 | 04:44 PM
  #147  
Red rooster's Avatar
Red rooster
Three Wheelin'
 
Joined: Dec 2004
Posts: 1,779
Likes: 1
From: Halifax, Nova Scotia , Canada
Default

Loren,
We are trying to lead a guy, who doesnt understand using a scope , along a path using the least technical terminology possible.
This is not a proper occaision for anyone try to demonstrate their respective technical prowess !
If it helps , I graduated in Electronic Engineering 1967 and have been involved with Defense / Automotive development ever since.
I know very well just how Motronic operates but see little point in this constant nitpicking .

You are stating that the time frame of crank sensor edges is irrelevant. That is nonsense. The missing tooth pulse is defined by its start and finish edges , as are all subsequent timing pulses .
As for the Pin 1 drive pulse , would you like the map address for the control algorithm ? or any other function in a 964 DME ??

None of this helps David resolve his problem at all , which should be our primary objective.I hope you agree.

Geoff
Reply
Old Jan 21, 2007 | 06:30 PM
  #148  
Indycam's Avatar
Indycam
Nordschleife Master
 
Joined: Sep 2004
Posts: 5,061
Likes: 2
From: not in HRM
Default

"which should be our primary objective"
How about , ONLY , objective ?

I know I'm nobody to tell anyone anything but ,
all this about edge , not edge , front / back side , bite me , etc , not really at all important in this car repair , is it ?

Well worth a new thread maybe ?
Reply
Old Jan 21, 2007 | 07:08 PM
  #149  
Red rooster's Avatar
Red rooster
Three Wheelin'
 
Joined: Dec 2004
Posts: 1,779
Likes: 1
From: Halifax, Nova Scotia , Canada
Default

Indycam,
I stand corrected ! You are 100% right.
Being from the UK, I understand Davids predicement very well ,hence the help.

Lets hope that tomorrow we can get that motor running!

All the best

Geoff
Reply
Old Jan 21, 2007 | 07:21 PM
  #150  
Lorenfb's Avatar
Lorenfb
Race Car
20 Year Member
 
Joined: May 2003
Posts: 4,223
Likes: 102
From: SoCal
Default

"You are stating that the time frame of crank sensor edges is irrelevant."

The edge in itself is irrelevant for signal generation here, i.e. it's the relative voltage level of the
sine wave that provides the pulse. The 911SC ignition (and the early 928, Mercedes Benz)
which uses the edge dV/dT to generate an igntion signal. There the polarity of the edge
affected the triggering time, thus the ignition timing.

Yes, the thread does get off the main direction occasionally by mis-information being posted,
but that's one of the purposes of a forum, i.e. to allow the correct info to "surface".

The scope's settings to check the Pin 1 ignition signal are:

1. Voltage - 2 volts/cm
2. Time Base - 5 ms/cm

Note: If your probe is X10, then the volts setting is .20 volts/cm.
The scope's triggering is set to automatic.

As the engine is cranked, multiple pulses should appear. Also, check Pin 6
which is the tach signal that's basically the same (but 0 to 12 volts vs 0 to 5)
as the Pin 1 spark trigger signal. If Pin 6 has a signal, but no Pin 1, then:

1. bad Pin 1
2. shorted wiring
3. shorted ignition module input

"all this about edge , not edge , front / back side , bite me , etc , not really at all important in this car repair , is it "

But it is necessary, especially for those ignitions, e.g. 911SC, that it's critical.

Last edited by Lorenfb; Jan 21, 2007 at 07:36 PM.
Reply



All times are GMT -3. The time now is 02:58 PM.