Coming Soon: Canards
10-22-2008, 01:23 PM
#166
Rennlist Member
Ill insert my comments on your post below:
You said:
You can push over to negative g and do all of the above (plus make everyone on the aircraft sick), but it is not required. And this is what Glenn was trying to say, and was 100% correct in the way he said it.
My point was if you push over, you are putting "downforces "on the wings to escape the thermal. I think the terms are again confusing.
You said:
You can push over to negative g and do all of the above (plus make everyone on the aircraft sick), but it is not required. And this is what Glenn was trying to say, and was 100% correct in the way he said it.
My point was if you push over, you are putting "downforces "on the wings to escape the thermal. I think the terms are again confusing.
10-22-2008, 01:30 PM
#167
Rennlist Member
Just like physics. engergy can not be created nor destroyed.
There is a reason for every event in the universe. Im wrong sometimes just as you are Jim.
The problem with the list is the written word can be misunderstood. We got into the discusion regarding aero aids and started to talk aero, using racing terms. we couldnt even get the class of the devices straight. canards, wings, winglets, diveplanes, etc.
Mk
There is a reason for every event in the universe. Im wrong sometimes just as you are Jim.
The problem with the list is the written word can be misunderstood. We got into the discusion regarding aero aids and started to talk aero, using racing terms. we couldnt even get the class of the devices straight. canards, wings, winglets, diveplanes, etc.
Mk
Jason you will find that Mark is never wrong......just misunderstood He presents a constantly shifting target and ALWAYS gets in the last word ! Need not be correct or accurate , simply the last word. Remember those who race MUST believe that they can WIN the race or they would not race and if they do not win it was because some one else had a better car , more money , new tires , a pit crew , or there was a Voodo Doll in their image with pins stuck in it. This should complete the hijacking of this thread
He presents a constantly shifting target and ALWAYS gets in the last word ! Need not be correct or accurate , simply the last word. Remember those who race MUST believe that they can WIN the race or they would not race and if they do not win it was because some one else had a better car , more money , new tires , a pit crew , or there was a Voodo Doll in their image with pins stuck in it. This should complete the hijacking of this thread 
10-22-2008, 01:45 PM
#169
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That settles it I am going to buy a Canard ......and roast it ! been a while since I have eaten duck and far too long since I cooked a Goose.
10-22-2008, 02:31 PM
#174
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An object in motion remains in motion till it hits a brick wall.
If lift of wing/body = gravity, then there is net no up or down operating on ze aeroplane.
But there is constant Descent if the aeroplane is traveling towards the ground.
As in it is flying not parallel to the ground and is moving towards the ground plane at a certain rate of descent. (not counting the curvature of the planet blob you are on)
Unless you use Amzoil. Then you'll fly forever even in a glider.
10-22-2008, 02:36 PM
#175
Rennlist Member
Your right, and I was not making myself clear. I will even go so far as to say I was wrong in that statement. yes, if there are equal forces, there will be no acceleration and you can have a constant decent. What I was trying to convey, was to do this you need varied input from the canard, or elevator to keep the balance of forces. sure, a rock dropped will accelerate until the forces of gravity equal the forces of drag. a car at a top speed of 200mph is no longer accelerating, due to a balance of the force of thrust and drag, rolling friction, etc.
mk
mk
An object in motion remains in motion till it hits a brick wall.
If lift of wing/body = gravity, then there is net no up or down operating on ze aeroplane.
But there is constant Descent if the aeroplane is traveling towards the ground.
As in it is flying not parallel to the ground and is moving towards the ground plane at a certain rate of descent. (not counting the curvature of the planet blob you are on)
Unless you use Amzoil. Then you'll fly forever even in a glider.
If lift of wing/body = gravity, then there is net no up or down operating on ze aeroplane.
But there is constant Descent if the aeroplane is traveling towards the ground.
As in it is flying not parallel to the ground and is moving towards the ground plane at a certain rate of descent. (not counting the curvature of the planet blob you are on)
Unless you use Amzoil. Then you'll fly forever even in a glider.
10-22-2008, 02:40 PM
#177
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Brain teaser: We define '1G' as being the force on an object at the surface of the Earth(generally sea level), at rest. From the point of view of gravity, the center of the Earth is used for calculations of it's mass constant in the Solar System. If we move away from the surface vertically, the gravitational pull decreases. What would happen if we drove a burrowing 928 into the Earth toward it's center?
Would the 'G' force of gravity increase, decrease, or remain the same as we descend into the center (hades)? Remember G forces decrease, as we move away from the center of the Earth. Defend your answer.
BTW, I do know the right answer, and there is one and only one right answer.
Would the 'G' force of gravity increase, decrease, or remain the same as we descend into the center (hades)? Remember G forces decrease, as we move away from the center of the Earth. Defend your answer.
BTW, I do know the right answer, and there is one and only one right answer.
10-22-2008, 02:46 PM
#179
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as you sit in the core, (after traveling to the core) you would feel less and less gravitational pull. In the core, if you were sitting in this 928 that burrowed to the center of the earth, you would be floating in space. however the pressure might be so great as to squish you into molden slag.
thats my guess.
edit, trick question! ok, the gravitational pull is still present. it would just be half , cancelling out in the opposite directions
if you drilled a hole and dropped your car through the hole in the earth , coming out to china, you would accelerate all the way to the center, and then decelerate as you came to rest just at the other side. the time it takes to do this would be the same, no matter where the hole through the earth was drilled . (eg: calif to china, N.Y. to california, N.Y. to africa, N.Y. to south pole, etc.
mk
thats my guess.
edit, trick question! ok, the gravitational pull is still present. it would just be half , cancelling out in the opposite directions
if you drilled a hole and dropped your car through the hole in the earth , coming out to china, you would accelerate all the way to the center, and then decelerate as you came to rest just at the other side. the time it takes to do this would be the same, no matter where the hole through the earth was drilled . (eg: calif to china, N.Y. to california, N.Y. to africa, N.Y. to south pole, etc.
mk
Brain teaser: We define '1G' as being the force on an object at the surface of the Earth(generally sea level), at rest. From the point of view of gravity, the center of the Earth is used for calculations of it's mass constant in the Solar System. If we move away from the surface vertically, the gravitational pull decreases. What would happen if we drove a burrowing 928 into the Earth toward it's center?
Would the 'G' force of gravity increase, decrease, or remain the same as we descend into the center (hades)? Remember G forces decrease, as we move away from the center of the Earth. Defend your answer.
BTW, I do know the right answer, and there is one and only one right answer.
Would the 'G' force of gravity increase, decrease, or remain the same as we descend into the center (hades)? Remember G forces decrease, as we move away from the center of the Earth. Defend your answer.
BTW, I do know the right answer, and there is one and only one right answer.
10-22-2008, 02:49 PM
#180
Man of many SIGs
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Using Gauss' law we can have the folowing equation :
F(r) = G(4p*r*rho*m)/3
with rho is the density of the earth,
m : mass of the thing going to the earth center.
r : distance to the center.
The key point is that when you go into the earth center, the mass behind you will not have any gravitational force on you, it cancels out. So at the earth center, the gravitational force is zero.
F(r) = G(4p*r*rho*m)/3
with rho is the density of the earth,
m : mass of the thing going to the earth center.
r : distance to the center.
The key point is that when you go into the earth center, the mass behind you will not have any gravitational force on you, it cancels out. So at the earth center, the gravitational force is zero.