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What does terminal Z do?

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Old 01-12-2014 | 02:57 AM
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Default What does terminal Z do?

More wiring questions, hopefully someone has been here before.
This is on a '79. I couldn't find terminal Z leads in the wiring diagrams for any year.

Terminal Z is the small 6 post terminal.

The terminal posts are listed in the wiring diagram, but the leads are not shown. This pic shows Z2,Z3, and Z4, but no wire leads coming out of them.



This pic shows Z1 and Z6 being jumpered




Here's a pic of the actual plug and what is connected to it:




I'm trying to determine where the plugs go.

The white plug has a red and red/wht lead, I don't know what this should be powering. Possibly the sun roof ( my car did not come with one).

The twin triple plugs to the right are identical, which leads me to believe they run to the doors.

The plug at the top I don't believe plugged into anything, because the jumper (which happens to bridge Z1 and Z6 as shown in the wiring diagram) would prevent it from doing so.

Anyone have any idea what this plug powers?

Thanks for the help.

Last edited by atb; 01-12-2014 at 10:21 AM.
Old 01-12-2014 | 03:21 AM
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Adam, that is not so much a terminal, but more plug Z on the CE panel, the number beside it the pin in the plug.
I'm on my phone atm or I'd look up the wiring diagram and tell you what function it has.
I know reading the diagrams can be tough, but the info is all there. Lol
Old 01-12-2014 | 10:40 AM
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Hey Colin,

This is the first time I've come across wiring that doesn't appear to be in the wiring diagram. The twin plugs should've been easy to find, they both have the same leads, brn/gn, brn,brn/red. I've looked on every sheet for the same wire color/plug combo and didn't see it. Since a lot of the track car wiring was gutted before I got to it, it's likely some if not all of this harness wasn't connected. Just want to make sure none of the leads are ignition or fuel pump related.
It would be awesome to get a second set of eyes on the wiring diagram to see what I'm missing. I wonder if it's alarm related?
Old 01-12-2014 | 10:45 AM
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Adam

Plug Z is for the Alarm system (optional on many years) look at the diagrams for an '82 - last page - first time its shown (same).

Z1 Alternator charge light (61)
Z2 Ground (31)
Z3 Alarm Power (30)
Z4 Fuel pump relay control
Z5 Trigger input (T-)
Z6 Alternator charge light (61) (alternatively sometimes ignition (15))

For alarm bypass you need a jumper between Z4 and either Z1 or Z6

For a simpler track car solution (and faster starting) just connect Z4 direct to ignition (15) no other connections are required

Alan
Old 01-12-2014 | 11:01 AM
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Awesome Alan!

So if I jumper Z1 and Z6 at the CE panel, can I then get rid of this harness altogether ? I'm trying to remove all non-essential wiring on this beast.

Thanks again
Old 01-12-2014 | 11:11 AM
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Z4 & Z6

OR

Z4 & Z1

If it were me - I'd locate an ignition (15) supply on the panel and connect that to Z4 - car will likely start faster..

Alan
Old 01-12-2014 | 11:24 AM
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If i get ign power to z4, will I still need to jumper it to z1 or z6?
Old 01-12-2014 | 12:21 PM
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No - thats all you need to do.
Old 01-26-2014 | 06:14 PM
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Terminal O8 is the exciter circuit wire, that comes from the alternator, through the 14 pin connector, through the fuse panel, and then to the pod and through the alternator warning light.

I'm really trying to simplify the track car wiring. If I take the exciter circuit lead from the alternator, and run it to my battery master switch (black wire on small terminal on bottom pic right side) and then run a lead from the other small post to the positive side of the battery, will the exciter circuit still function? I understand that I lose the alt light warning, but that's kind of the point, I don't want to be at the mercy of that bulb.



Old 01-26-2014 | 07:59 PM
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You can eliminate the bulb - however I would add a resistor in the circuit - ~47 ohms 5W should work OK.

Alan
Old 02-16-2014 | 03:56 PM
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Any chance there's a typo here Alan, I can find 47 ohms / 0.5W , or .47 ohms /5W.

Adam



Originally Posted by Alan
You can eliminate the bulb - however I would add a resistor in the circuit - ~47 ohms 5W should work OK.

Alan
Old 02-16-2014 | 04:13 PM
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No that was correct (its approx though - so 50ohms would also be fine & any higher wattage would be fine).

http://www.ebay.com/itm/10W047-47-Oh...item5d467c2858

Alan
Old 02-16-2014 | 04:41 PM
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Thank you sir! It's funny that it was the counter person at Radio Shack who said that I must be decimal point off on one of the specs. Tempted to go back and show him your link.:-)
Old 02-17-2014 | 02:28 AM
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Originally Posted by atb
Thank you sir! It's funny that it was the counter person at Radio Shack who said that I must be decimal point off on one of the specs. Tempted to go back and show him your link.:-)
He must not be very bright - resistance valves come in fixed values at various integer powers of 10: so 0.47 ohms, 4.7 ohms, 47 ohms, 470 ohms, 4700 ohms 47K ohms, 470K ohms etc etc (47 is one of the standard resistance values).

So its very odd he would think that...

Alan



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