Notices
928 Forum 1978-1995
Sponsored by:
Sponsored by: 928 Specialists

Boost Curve/Efficiency of Whipple vs Centrifugal

Thread Tools
 
Search this Thread
 
Old 02-20-2004, 10:46 AM
  #16  
Lagavulin
Three Wheelin'
 
Lagavulin's Avatar
 
Join Date: Mar 2003
Location: New Berlin
Posts: 1,286
Likes: 0
Received 1 Like on 1 Post
Default

Originally posted by SteveM928
So at that 500+ hp, 874 cfm, 11psi level, it looks like the Lysholm's efficiency is about 60%, the Vortech S-Trim about 70% , and the Vortech T-Trim about 72%. That means that a smaller amount of the power put into the Vortechs ends up being used to make heat instead of boost at that horsepower, boost, and cfm point. Since the goal is the amount of boost you want, it would mean that more power would be required by the Lysholm to get that level of boost, since more of the power being put into that one would be used producing heat. In order to run that much boost with the same detonation protection on otherwise equal engines, you'd also have to get rid of more of that heat with a better intercooler on the Lysholm than the ones on the Vortechs. You'd need either a bigger or more efficient intercooler with the Lysholm to get to the same intake temperature as the Vortechs, but even then you would have still had to be putting more power into the Lysholm initially. Interesting comparison of the different units for the specific goal or application used for the example. It also really helps to show that knowing the power level you want, or may want to someday upgrade to, can be pretty important when planning out the combination that will work out best for you.
Hmm, that looks like an accurate assessment to me. What do you guys think?
Old 02-20-2004, 01:45 PM
  #17  
drnick
Drifting
 
drnick's Avatar
 
Join Date: May 2002
Location: New Zealand
Posts: 2,777
Likes: 0
Received 2 Likes on 2 Posts
Default

i dont think so.

"Since the goal is the amount of boost you want,.."

not in isolation, in my view. the amount of boost at a given road and engine speed is what is important. i only ever hear jap rice rockets caning around at max rpm and i cant seriously imagine driving allways at 6500 rpm in my 928, so what about the rest of the time?

i think that to focus on absolute max hp and efficency can be usefull but may also be so constricted as to miss some things, perhaps the point entirely!

im off snowboarding...
Old 02-20-2004, 01:48 PM
  #18  
John..
Three Wheelin'
 
John..'s Avatar
 
Join Date: Nov 2001
Location: Northern Kentucky
Posts: 1,446
Likes: 0
Received 0 Likes on 0 Posts
Default

Interesting point Nick, the same one I have been making on here for over a year now...

The Aerochargers have been successful on many car applications, including some GM applications for conceptual vehicles.
Old 02-20-2004, 02:36 PM
  #19  
blau928
Addict
Rennlist Member

 
blau928's Avatar
 
Join Date: Feb 2004
Location: Monterey Peninsula, CA
Posts: 2,374
Likes: 0
Received 16 Likes on 12 Posts
Default

I am curious if anyone has compared the discharge temperature at specific RPM or boost level of centrifugals vs lysholm blowers.. In addition, what about the engine load and aerodynamic resistance load in combination with the gearing throughout the powerband..

A quick tip on CFM to HP ratio... It takes about 1.5CFM of air for 1 HP...
Old 02-20-2004, 03:24 PM
  #20  
SteveM928
Instructor
 
SteveM928's Avatar
 
Join Date: Jan 2004
Location: Florida
Posts: 144
Likes: 0
Received 0 Likes on 0 Posts
Default

Originally posted by drnick
i dont think so.

"Since the goal is the amount of boost you want,.."

not in isolation, in my view. the amount of boost at a given road and engine speed is what is important. i only ever hear jap rice rockets caning around at max rpm and i cant seriously imagine driving allways at 6500 rpm in my 928, so what about the rest of the time?

i think that to focus on absolute max hp and efficency can be usefull but may also be so constricted as to miss some things, perhaps the point entirely!
And I can't seriously imagine always shifting at 3,500 RPM when wanting maximum power. To each his own I guess though. Looking at the charts to see the efficiencies at lower levels then might be more applicable in that case. At about 5psi and 450cfm the Lysholm chart shows an efficiency of a little under 60%. Both of the Vortechs show 72% efficiency at that 5psi and 450 cfm. So even at the lower boost and cfm you'd be at lower in the RPM range, the Vortechs would have a higher efficiency, be using less of the power put into them to create heat instead of boost, and require smaller or less efficient intercoolers to achieve the same intake temperature as the Lysholm. In case some of you are confusing the issues, I'm talking about the efficiencies of the different blowers, which is what the question starting the thread was asking about.
Old 02-20-2004, 07:50 PM
  #21  
Tony
Addict
Lifetime Rennlist
Member
 
Tony's Avatar
 
Join Date: May 2001
Location: Las Vegas
Posts: 14,676
Received 584 Likes on 305 Posts
Default

Hey Lags, schoolboy. THIS IS HOW YOU DO IT.

CFM = (cid x rpm x 0.5 x VE) / 1728

based on your dyno chart for 512rwhp...done at 5900rpm NOT 6500
CFM = (302ci x 5900rpm x 0.5 x 88%) / 1728 = 453.69cfm

So, the stock S4 at 5900rpm is consuming 453.69 cfm of air.


PR=(14.7psi + boost) / 14.7
PR=(14.7psi + 11psi) / 14.7 = 1.748 Bar


New CFM = (Orig CFM x PR)
New CFM = (453.69 cfm x 1.748 Bar) = 793.06cfm

So, your S4 at its 512 rwhp mark at 11psi is pushing 793.06 cfm of air through the engine....this is at 5900rpm!...not 6500

In a nut shell then you made your 500rwhp number at 793cfm , not 874?


Did i do that right?
I recalled from your post that you never hit redline or the limiter on your 512 pull so i went back to see what CFM you were actually pulling at the 512 point. Then based on the way you did your calcs, I just change 6500 to 5900 in the first equaion.

Ya left a bunch on the go pedal Lags!

Please correct me if my reasoning is flawed because my math, LIKE my spelling on here...is POIFECT!

Old 02-20-2004, 08:22 PM
  #22  
Lagavulin
Three Wheelin'
 
Lagavulin's Avatar
 
Join Date: Mar 2003
Location: New Berlin
Posts: 1,286
Likes: 0
Received 1 Like on 1 Post
Default

Originally posted by Tony
Hey Lags, schoolboy. THIS IS HOW YOU DO IT.
...
Did i do that right?
I recalled from your post that you never hit redline or the limiter on your 512 pull so i went back to see what CFM you were actually pulling at the 512 point. Then based on the way you did your calcs, I just change 6500 to 5900 in the first equaion.

Ya left a bunch on the go pedal Lags!

Please correct me if my reasoning is flawed because my math, LIKE my spelling on here...is POIFECT!
Nyuk, nyuk, nyuk, nyuk!

Yep, that's right!

When I did 492 rwhp I spun it pretty close to 6500 RPM which is pretty close to the 500 rwhp you were asking about. So as you noticed, there is usually a range based upon various factors. All in all, it will give you a good idea of what's happening, and get you in the ballpark.
Old 02-20-2004, 09:12 PM
  #23  
Tony
Addict
Lifetime Rennlist
Member
 
Tony's Avatar
 
Join Date: May 2001
Location: Las Vegas
Posts: 14,676
Received 584 Likes on 305 Posts
Default

eh...when 500 is a such big benchmark these days and worth a few bragging rights, 492 may as well be 400!



Old 02-20-2004, 09:22 PM
  #24  
Tony
Addict
Lifetime Rennlist
Member
 
Tony's Avatar
 
Join Date: May 2001
Location: Las Vegas
Posts: 14,676
Received 584 Likes on 305 Posts
Default

Ok, i guess i have a question on how to interpret/apply the info shown on these charts.

lets say you pulley this SC for a max rpm of 12000 (max is 13500). This flows 26m^3 or appx 918cfm. What determines the boost you end up with..8..11 or 13psi for example.

I feel like im missing some part of the equation?


Old 02-20-2004, 10:49 PM
  #25  
SteveM928
Instructor
 
SteveM928's Avatar
 
Join Date: Jan 2004
Location: Florida
Posts: 144
Likes: 0
Received 0 Likes on 0 Posts
Default

Originally posted by Tony
Ok, i guess i have a question on how to interpret/apply the info shown on these charts.

lets say you pulley this SC for a max rpm of 12000 (max is 13500). This flows 26m^3 or appx 918cfm. What determines the boost you end up with..8..11 or 13psi for example.

I feel like im missing some part of the equation?
As was calculated above, the stock normally aspirated 928 uses about 453cfm at 5,900 RPM. Let's say you want to spin the Lysholm that the chart is for at 12,000 RPM, at that same engine RPM of 5,900. As the chart shows, the Lysholm flows about 918 cfm then. The 918cfm of the blower divided by the 453cfm that the engine would take in at atmospheric pressure equals just over 2.0. The blower is pumping 2.0 times as much air as the engine normally could take in. Since the displacement of the engine stays the same, the pressure goes up by 2.0 times, for a pressure ratio of 2.0. Subtract the 14.7psi of normal atmospheric pressure and you end up with about 14.7psi of boost. At that blower speed, engine RPM, pressure ratio, and cfm flow, the Lysholm chart indicates that you'd be at 63% efficiency, that the intake air temperature would be increased from 20C (68F) to a little over 125C (257F), and the blower would be requiring about 55kw (73.7hp) to spin.

The above resulting boost is just the quick rough calculation. Things like the intercooler efficiency and pressure drop through it aren't factored in.

Last edited by SteveM928; 02-21-2004 at 12:50 AM.
Old 02-21-2004, 12:55 AM
  #26  
Tony
Addict
Lifetime Rennlist
Member
 
Tony's Avatar
 
Join Date: May 2001
Location: Las Vegas
Posts: 14,676
Received 584 Likes on 305 Posts
Default

Thanks a bunch Steve. Now it makes sense.
I can can see where i had things messed up in my head. In short CFM flow greater than the engine can take in at a given rpm becomes a certain amount of boost.

Old 02-21-2004, 12:39 PM
  #27  
BC
Rennlist Member
Thread Starter
 
BC's Avatar
 
Join Date: Dec 2001
Posts: 25,150
Received 82 Likes on 55 Posts
Default

That seems like alot of power to drive that positive displacement blower.

Do we have any charts that say how much power the Centrifugal is taking?
Old 02-22-2004, 04:08 PM
  #28  
SteveM928
Instructor
 
SteveM928's Avatar
 
Join Date: Jan 2004
Location: Florida
Posts: 144
Likes: 0
Received 0 Likes on 0 Posts
Default

Originally posted by BrendanCampion
Do we have any charts that say how much power the Centrifugal is taking?
This is more of another quick and rough calculation, but should at least give some idea for comparison. If the Lysholm is using 73.7hp with 63% efficiency, that means it would take 46.4hp at 100% efficiency. (73.7hp muliplied by .63) If you take the 100% efficiency figure of 46.6hp and divide by the 72% efficiency that the Vortechs have at that same boost and cfm level, you get 64.7hp required to drive them. Around 9hp less to drive the Vortechs than the Lysholm at that boost and cfm level. As was stated before, that extra power goes into making heat. The thing to really be more concerned about than the extra power lost to drive the Lysholm would be getting rid of that extra heat it produced. The extra heat is going to make it tougher to prevent detonation unless you get rid of it. I'm thinking that there's probably limited space under the hood of a 928 for intercoolers. I don't know how efficient the intercoolers that would be used with the Lysholm are compared to those that would be used with the Vortechs, so it's possible that you could get the intake charge temperatures the same for both. Then the difference would just be the extra horsepower that you used to turn the Lysholm.
Old 02-23-2004, 02:42 AM
  #29  
Tony
Addict
Lifetime Rennlist
Member
 
Tony's Avatar
 
Join Date: May 2001
Location: Las Vegas
Posts: 14,676
Received 584 Likes on 305 Posts
Default

Thats pretty interesting, thanks again Steve. I haven't been able to find data on the vortechs Delta T. Anyone have a source?

If some of you haven't seen this, its pretty trick engine animation of the GT 40
http://www.fordvehicles.com/fordgt/m...E_VIDEO&bhcp=1

Old 02-23-2004, 04:05 AM
  #30  
mspiegle
Three Wheelin'
 
mspiegle's Avatar
 
Join Date: Nov 2003
Location: Los Angeles, CA
Posts: 1,577
Likes: 0
Received 0 Likes on 0 Posts
Default

that is an AWESOME video, thanks tony.



Quick Reply: Boost Curve/Efficiency of Whipple vs Centrifugal



All times are GMT -3. The time now is 05:50 AM.