Lowering early 944 front end without lowering springs
#2
Burning Brakes
Join Date: Nov 2003
Location: Baltimore MD
Posts: 962
Likes: 0
Received 0 Likes
on
0 Posts
Let some air out of your front tires. That should lower it a bit.
Actually, I think there are a couple camber plates you can get that will lower your car by and inch or so. That might not be too much easier then getting something like paragon's ride hight kit though.
Actually, I think there are a couple camber plates you can get that will lower your car by and inch or so. That might not be too much easier then getting something like paragon's ride hight kit though.
#3
Race Director
You CAN'T!
There is no adjustment. You must replace the front springs or change to ride height adjusting coilovers.
The only 924/944/968 that can lower the front without new springs is the 944 Turbo S or 968/944S2 with M030. These cars have factory adjustable spring perches.
There is no adjustment. You must replace the front springs or change to ride height adjusting coilovers.
The only 924/944/968 that can lower the front without new springs is the 944 Turbo S or 968/944S2 with M030. These cars have factory adjustable spring perches.
Trending Topics
#11
RL Community Team
Rennlist Member
Rennlist Member
Originally Posted by Serge944
Nothing wrong with cutting springs, if done properly. Your spring rate will increase, as well.
#13
Race Car
Cutting the spring will not change anything other than causing the car to bottom out. Simple physics F=KX where force equals spring CONSTANT times distance travelled. The spring rate of the stock spring is CONSTANT so cutting it will absolutely not make it stiffer. It will reduce the force it exerts on the car if you reduce X, which is the distance you can compress the spring, meaning in a compressional force of a bump, your car is more likely to bottom out causing you to go out of control.
#14
Rennlist Member
Originally Posted by Legoland951
Cutting the spring will not change anything other than causing the car to bottom out. Simple physics F=KX where force equals spring CONSTANT times distance travelled. The spring rate of the stock spring is CONSTANT so cutting it will absolutely not make it stiffer. It will reduce the force it exerts on the car if you reduce X, which is the distance you can compress the spring, meaning in a compressional force of a bump, your car is more likely to bottom out causing you to go out of control.
All a spring is is a coiled torsion bar. By cutting it youre reducing the leverage and therefore increasing the spring rate. How do you think the spring is made initially.
Rate(n) = (ShearModulus)*(WireDia(n))^4 / ( 8 * (NumberOfActiveCoils(n)) * (MeanCoilDia(n)) )
This formula is used and this is how you get the required amount of coils, coil diameter, and overall length of the spring.
What happens if you put two 200 lb springs in series? The result is a 100 lb spring. Spring rates are added like capacitors total = 1/(1/R1 + 1/R2....).
#15
Rennlist Member
Join Date: Apr 2006
Location: Chicago
Posts: 696
Likes: 0
Received 0 Likes
on
0 Posts
Interesting to see the use of Hook's law and bulk modulus used here..I have seen everything. If I knew how, I would take a screen shot of this and show it to my undergrad students to prove how useful this stuff is and how applicable it is to every day life. You guys Rock!!!!