Need engineering help to beat a dead horse
#16
Great discussion. Confirming the others, a radian is any circle's circumference divided by its diameter. Units are meter/meter, in/in, mm/mm, etc. The units cancel regardless of the unit used.
You cover only the case of an instant where the acceleration is 41.8 rad/sec or averages 41.8 rad/sec. Assumptions are necessary to simplify calculations, and that is a good assumption to use. In reality the angular acceleration is variable. I drove deoxford's LWF car back-to-back with my DMF car. There is a noticeable difference in the way the revs drop during gear changes. The LWF also makes a big difference if you blip the throttle - the engine revs noticeably more quickly with the LWF. The car's overall acceleration depends on power output from the engine, and total inertia (both linear and angular) of the car. There we did not see much difference.
I want the LWF in my car - just for the more responsive feel. I am not going to drop the engine to make the switch, but I will have the LWF first time the engine is out for any reason. If you have the engine out.....
You cover only the case of an instant where the acceleration is 41.8 rad/sec or averages 41.8 rad/sec. Assumptions are necessary to simplify calculations, and that is a good assumption to use. In reality the angular acceleration is variable. I drove deoxford's LWF car back-to-back with my DMF car. There is a noticeable difference in the way the revs drop during gear changes. The LWF also makes a big difference if you blip the throttle - the engine revs noticeably more quickly with the LWF. The car's overall acceleration depends on power output from the engine, and total inertia (both linear and angular) of the car. There we did not see much difference.
I want the LWF in my car - just for the more responsive feel. I am not going to drop the engine to make the switch, but I will have the LWF first time the engine is out for any reason. If you have the engine out.....
#17
Precisely - you have to choose a specific acceleration to result in some amount of torque.
In other words, choose a beginning RPM, ending RPM, and the time it takes to get from one to the other, or the math doesnt' work.
I chose 4-6k in 5 seconds because I thought that might represent an approximation of flat out in 3rd or 4th gear. If you make the rev change larger and/or the time duration shorter between the specified revs, the acceleration is much greater and so would the resulting torque delta. Free revving is a very large RPM delta in very small time delta, so I would expect a pronounced difference between the 2 in that case. AKA more responsive for rev-matching during shifting.
In other words, choose a beginning RPM, ending RPM, and the time it takes to get from one to the other, or the math doesnt' work.
I chose 4-6k in 5 seconds because I thought that might represent an approximation of flat out in 3rd or 4th gear. If you make the rev change larger and/or the time duration shorter between the specified revs, the acceleration is much greater and so would the resulting torque delta. Free revving is a very large RPM delta in very small time delta, so I would expect a pronounced difference between the 2 in that case. AKA more responsive for rev-matching during shifting.
#19
your angular moment of inertia (AMI) approximation to a cylinder of 4" radius... is a killer misapproximation. Real life, it's a big ol' beefy platter. A platter's AMI is proportional to the square of the platter radius. Meaning, an oz. of material 2" away from the crank centerline is only *1/9th* the AMI contributor of his "brother"-oz., 6" out from centerline -- though both are equal distance from that 4 inch cylinder line.
#21
#22
First approximation is that we can eliminate the "axial" dimension, and for the purposes of inertia, treat it as a 2-dimensional object, like a disk.
I could either choose the moment of inertia of a:
disk, I= (mr^2)/2
"infinitely thin-walled hollow cylinder", I=mr^2
or
"thick walled cylinder" I= .5m(r1^2 + r2^2) r1 and r2 being inner/outer radius
Clearly, disk is the worst choice because of the empty space in the center. Casual glance indicates most of the mass is in the friction surface region (througout the axial dimesion of course), then there's the ring gear and sensor teeth outside of that. The thick-walled cylinder would probably have been a better formula to use. I chose thin-walled because the math was easier and I just kind of guessed where the "radial center" of mass would be at 4 inches. This was a total swag - but I know there is indeed some radius of thin-walled cylinder that makes the moment exactly match that of the probably more realistic thick-wall cylinder moment. Re-doing this with the thick-wall cylinder formula *might* yield better accuracy but you still have to take a swag at what the inner and outer radii are, accounting for the fact that there is an irregular mass distribution as you move along the radius of the flywheel.
I could either choose the moment of inertia of a:
disk, I= (mr^2)/2
"infinitely thin-walled hollow cylinder", I=mr^2
or
"thick walled cylinder" I= .5m(r1^2 + r2^2) r1 and r2 being inner/outer radius
Clearly, disk is the worst choice because of the empty space in the center. Casual glance indicates most of the mass is in the friction surface region (througout the axial dimesion of course), then there's the ring gear and sensor teeth outside of that. The thick-walled cylinder would probably have been a better formula to use. I chose thin-walled because the math was easier and I just kind of guessed where the "radial center" of mass would be at 4 inches. This was a total swag - but I know there is indeed some radius of thin-walled cylinder that makes the moment exactly match that of the probably more realistic thick-wall cylinder moment. Re-doing this with the thick-wall cylinder formula *might* yield better accuracy but you still have to take a swag at what the inner and outer radii are, accounting for the fact that there is an irregular mass distribution as you move along the radius of the flywheel.
#24
First approximation is that we can eliminate the "axial" dimension, and for the purposes of inertia, treat it as a 2-dimensional object, like a disk.
I could either choose the moment of inertia of a:
disk, I= (mr^2)/2
"infinitely thin-walled hollow cylinder", I=mr^2
or
"thick walled cylinder" I= .5m(r1^2 + r2^2) r1 and r2 being inner/outer radius
Clearly, disk is the worst choice because of the empty space in the center. Casual glance indicates most of the mass is in the friction surface region (througout the axial dimesion of course), then there's the ring gear and sensor teeth outside of that. The thick-walled cylinder would probably have been a better formula to use. I chose thin-walled because the math was easier and I just kind of guessed where the "radial center" of mass would be at 4 inches. This was a total swag - but I know there is indeed some radius of thin-walled cylinder that makes the moment exactly match that of the probably more realistic thick-wall cylinder moment. Re-doing this with the thick-wall cylinder formula *might* yield better accuracy but you still have to take a swag at what the inner and outer radii are, accounting for the fact that there is an irregular mass distribution as you move along the radius of the flywheel.
I could either choose the moment of inertia of a:
disk, I= (mr^2)/2
"infinitely thin-walled hollow cylinder", I=mr^2
or
"thick walled cylinder" I= .5m(r1^2 + r2^2) r1 and r2 being inner/outer radius
Clearly, disk is the worst choice because of the empty space in the center. Casual glance indicates most of the mass is in the friction surface region (througout the axial dimesion of course), then there's the ring gear and sensor teeth outside of that. The thick-walled cylinder would probably have been a better formula to use. I chose thin-walled because the math was easier and I just kind of guessed where the "radial center" of mass would be at 4 inches. This was a total swag - but I know there is indeed some radius of thin-walled cylinder that makes the moment exactly match that of the probably more realistic thick-wall cylinder moment. Re-doing this with the thick-wall cylinder formula *might* yield better accuracy but you still have to take a swag at what the inner and outer radii are, accounting for the fact that there is an irregular mass distribution as you move along the radius of the flywheel.
#25
[God, how I promised myself not to jump back into this physics heavy-lifting... ]
An old engineer I respect once cautioned me, "Mother Nature doesn't make bookkeeping errors." -- by which he meant, if your numbers don't match reality, reassess your numbers and presumptions -- don't try to argue w/ reality.
(It cautioned me that Mother Nature isn't tolerant of My bookkeeping errors -- they'll be revealed -- always. Anyway...)
I got to thinking -- LWFs really come into their own during a down-shift throttle blip, more so than a flat out acceleration run. And your engine's response isn't a linear ramp up to that blipped rpm. Instead, it's more S-shaped: a 'tip-in' relatively slow to action rise, followed by a *real* steep climb of rpms, and trailing off to a 'muted' topping out arrival to that upper rpm.
And it's that middle section's steep slope where the LWF really shows itself in real numbers. (Indeed, slope of the rpm vs. time curve is one definition of angular acceleration.)
Least, that's the story I'm going with for now ...
An old engineer I respect once cautioned me, "Mother Nature doesn't make bookkeeping errors." -- by which he meant, if your numbers don't match reality, reassess your numbers and presumptions -- don't try to argue w/ reality.
(It cautioned me that Mother Nature isn't tolerant of My bookkeeping errors -- they'll be revealed -- always. Anyway...)
I got to thinking -- LWFs really come into their own during a down-shift throttle blip, more so than a flat out acceleration run. And your engine's response isn't a linear ramp up to that blipped rpm. Instead, it's more S-shaped: a 'tip-in' relatively slow to action rise, followed by a *real* steep climb of rpms, and trailing off to a 'muted' topping out arrival to that upper rpm.
And it's that middle section's steep slope where the LWF really shows itself in real numbers. (Indeed, slope of the rpm vs. time curve is one definition of angular acceleration.)
Least, that's the story I'm going with for now ...
#26
[God, how I promised myself not to jump back into this physics heavy-lifting... ]
An old engineer I respect once cautioned me, "Mother Nature doesn't make bookkeeping errors." -- by which he meant, if your numbers don't match reality, reassess your numbers and presumptions -- don't try to argue w/ reality.
An old engineer I respect once cautioned me, "Mother Nature doesn't make bookkeeping errors." -- by which he meant, if your numbers don't match reality, reassess your numbers and presumptions -- don't try to argue w/ reality.