Front end question
11-05-2002, 10:36 AM
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Front end question
As some of you know I bought my 1982 928 with a little front end damage. It looked as though it got parked real hard under the rear end of a truck that had a high bed. It is all put back together now and I have been enjoying it. But I have notice that if I look straight at it from the front the wheels appear to lean in at the top. They are both the exact same as though the car is squatting in the front. I did not think too much about this until I read the post about lowering the car and something was mentioned. Is this normal? 
Chucker
1982 928 White
Chucker
1982 928 White
11-05-2002, 10:50 AM
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Perhaps the front end has sagged a bit. The front wheels should have a slight bit of negative camber (tops closer together), but it is pretty small.
Get a 24" level and two identical spacers about an inch long. Tape the spacers to the level so that they match the wheel rim. With the car on a level spot, put the level vertically against the wheels. With the level plumb (vertical), the bottom spacer should be against the rim and there should be about an 0.020" gap between the top spacer and the rim. If there is much more than this, you probably need to check the ride height and alignment.
The front fender lips should be about 27" from the ground.
Get a 24" level and two identical spacers about an inch long. Tape the spacers to the level so that they match the wheel rim. With the car on a level spot, put the level vertically against the wheels. With the level plumb (vertical), the bottom spacer should be against the rim and there should be about an 0.020" gap between the top spacer and the rim. If there is much more than this, you probably need to check the ride height and alignment.
The front fender lips should be about 27" from the ground.
11-05-2002, 11:20 AM
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Wally,
I think you missed a decimal - must be 0.20"
When I measure on my tires the vertical distance is 530 mm (20")
Camber front to be - 30' - Tangens* to 30' is 0.0087 - That makes: 530 x 0.0087 = 4.6 mm (3/16")
Camber back to be - 40' - Tangens* to 40' is 0.01175 - That makes: 530 x 0.01175 = 6,2 mm (1/4")
*)I do not know the name in English - I.e. matematic triangular
I think you missed a decimal - must be 0.20"
When I measure on my tires the vertical distance is 530 mm (20")
Camber front to be - 30' - Tangens* to 30' is 0.0087 - That makes: 530 x 0.0087 = 4.6 mm (3/16")
Camber back to be - 40' - Tangens* to 40' is 0.01175 - That makes: 530 x 0.01175 = 6,2 mm (1/4")
*)I do not know the name in English - I.e. matematic triangular
