Jerry Feather

Duplicate.

Jerry Feather

How does weight equal volume? What if the part floats? I think this will work, if at all, only North of 45 Degrees North Latitude.

Bertrand Daoust

It will work if it is completely immerse.
If it floats, you'll need to find a way to immerse it completely and deduct what you used to keep it under the surface.

The density of water is 1.
So one ml = 1g.

The volume the part takes will be equal the it's weight.
Edit: Not it's weight but it will be equal to the weight of the water displaced.

Dave928S

A basic measurement principle in physics, with the moment of discovery attributed to Archimedes .... https://en.wikipedia.org/wiki/Eureka_(word)

Jerry Feather

OK, but there is no "Eureka" here! As suggested by Bertrand when, we suspend the object in the bucket of water and check the weight, the water, although now displaced around the object, is still in the bucket, so the weight of it will not change. The only thing that might change the scale reading is how much downward pressure one might be using to hold the object under, if it floats, and maybe a negative weight related to how much of the object is being held above the bottom of the bucket if it otherwise will sink. Neither weight indication is going to relate at all to the weight of the water displaced, since it is still in the bucket.

And maybe south of 45 degrees south latitude?

Jerry Feather

I don't think so. The volume of the object will be equal to to weight of the water displaced.

How are you going to separate the water displaced from the water not displaced? Or otherwise measure it by itself.

Maybe doing what Randy suggested in the first place--with a graduated cylinder, or some similar substitute.

Bertrand Daoust

Just do what Randy suggest and you'll be fine.

We're not going anywhere here.

You can do whatever you want at the end... But my method would work.

Like Dave said, it's not mine, it's Archimedes!

Jerry Feather

OK, I'll back off. I figured it out, but I haven't figured out why. I understand about Archimedes, but I can't figure out why the object suspended in the water appears to weigh the same as water no matter what it is.

I did a test to see if I could show what I thought was the case, with different density objects suspended in the water, and I found that You, Bertrand are exactly correct. I went out in the shop and found a chunk of 3/4 inch aluminum plate cut off of something and then cut a piece of wood to almost the exact same size. Then I suspended them each separately in a jug of water on my scale and they each show the same weight.

I'm not sure now what my scale is reading in, but when I figure that out I'll know what one of my ***** volume is. Here are some pictures of the test.

Jerry Feather

Here's the GTS mold full of molding compound in the upper half of the mold. I think it poured much better than the other one and I'm pretty sure it'll open without any bubbles.

Jerry Feather

Based on Bertrand's revelation and my proving it to myself, I found that the early shift **** displaces .158 or so pounds. That comes out to 71 grams or 71 ml. When I get the GTS **** out of the mold I'll measure it the same way and then know almost exactly how much rubber compound to put in the 100 ml syringe. Thanks Bertrand. Sorry about all my ignorance.

Bertrand Daoust

The shifter shown here that weight .156 pound is 4.27... square inches. Less the wire that you use that is inside the water which I would not worry here.

Keep up the good work Jerry.

Bertrand Daoust

Right Jerry.
Bad phrasing. Sorry.
I edited my post.

No need to be sorry Jerry.

Not at all.

Again, keep up the good work.

Jerry Feather

And there it is--freshly opened and a perfect mold of the upper half of the GTS ****. As with the first half, the wooden extension I had glued onto the bottom end stayed in the mold, but it has release on it so it will come out pretty easily by picking with a small chisel. Then I can smooth the transition with the chisel and files. The four round registration bumps I put in it also came or perfect.

Jerry Feather

The weight of the water displaced by the GTS **** suspended in the water in the jug is .210 pounds. That is with the 3/4 inch extension broken off. I think that means that it is going to take something over 100 ml of rubber compound to cast it. What that means is that I'll need to mix up just under 200 ml of compound, then start with the original **** and inject its mold first from a full 100 ml syringe, then use the rest of the syringe into the GTS mold, then finish the GTS mold with another nearly full syringe of compound.

Jerry Feather

It seems to calculate out that it will take nearly one pound of rubber compound to form two each of these shift *****. I have one pound and it costs nearly $50 on eBay. There is a better source online for 10 pounds for $344 including shipping. If this stuff works out with what I have I'll order that.

After I get the casting of ***** refined, to the extent that it isn't yet, then I'll have another effort to complete in making a somewhat similar set of forms to assist with the covering these with leather in much the same fashion as they were done by or for the factory.