bureau13

Strangely, I thought they looked a lot better in your picture than in the pic of them on an actual car.

mark kibort

i think the thin spoke anteras look much better. I would pass.

dont worry about the weight... its only as if 1.4-1.3X of that extra weight (vs a stock rim) is sitting in the car as far as performance. (e.g. if the rim weighs 5 lbs more each, thats like , not 20 lbs sitting in the car, but 25lbs. same effect as the weight of 4 extra gallons of gas in the tank.

christiandk

Not the worst I have seen but why mess with perfection?

vetter59

After pondering over these wheels for a couple days, I think I am going to pass on them. The owner, who is a friend let me take them home to check them out. They are definitely un-common and un-usual, and might look really good on the right 928, like a Stroesk possibly? I looked them over very well and don't see any curb rash, dings or damage. The asking price is $350, plus shipping, and I can give you owner contact # also I will be at SITM this weekend. I currently have 16" Phone Dials, and Manholes also -but I am leaning towards 17" Cup 2's or 18" Carrera 3's -but don't want to roll rear quarter panels

whiteNSXs

Mark,
The difference is in the "unsprung" weights of the wheels. 5 extra lbs on a wheel will greatly affect handling and acceleration due to the much increase in rotational inertia.
Steve

Dave928S

^^ and braking.

The wheel is much like a flywheel in effect ... try slowing down or speeding up a heavy flywheel versus a light one. A bit pointless having light wheel nuts and hubs, and massive brakes, if you counteract them with a heavy wheel.

mark kibort

Steve,
There are two parts to consider. Handling, and then acceleration.
lets talk about acceleration. as i said, that weight on the wheel has the EXACT effect of acceleration as if 1.4x that weight was sitting in the car.
(easy to calculate rotational inertia to translational conversion). its actually less, due to that calculation being all the weight in the outer ring of the wheel, when actually, usually, most of the weight difference is in the center, so a more accurate equivalence is 1.2-1.3x the weight as if it was sitting in the car. SO......... this doesn't "greatly effect " acceleration , agreed?? (e.g. 5lbs per wheel will be less than if 25lbs were sitting in the car as its effect on acceleration)

next, unsprung weigh as far as handling? yes you are technically correct.... this is also true. but we are talking about several effects here. And , the difference between two wheels and tire, as well as unsprung suspension components, might be less than 10% for a 50lb wheel and tire with 10-20lbs of other stuff connected to it and a 5 lb savings. so, this is not " greatly" effecting" anything. there is the control of this mass with the shock, and there is gyroscopic forces. However, if you are on a smooth track and the steering inputs are not like what you see at Sebring's final turn, this difference will largely go unoticalbe. Ive often switched out between a 5lb heavier set of rims and tires and noticed nothing as far as handling and steering feel.

mark kibort

Again, you and steve have missed an important point.

no, the wheel is NOT like a flywheel effect... the flywheel and driveline have that effect. not the wheel and tire. the car and rotating wheels and tires are tied to the road via the grip of the tires. speediing up a wheel and tire is very close to speeding up and slowing down an mass in a linear path. (its inertia and its called translational inertia) the equation is real simple.

the wheel is NOT alone here. it is just one part of the translational Inertia of the entire car. rotational will add to it, but we are talking wheel here. the wheel is smaller than the entire diameter of the wheel and tire and the mass is spread out relatively evenly.
It not pointless to have lightweight "ANYTHING" (lugs, tires, etc) because all of this is a part of the entire car, and has the same effect (plus a small rotational cost based on mass 's position on the rotation element.)

so, again, the translational equivalent for the rotating weight if it is evenly spread out on a typical wheel, would be near 1.3x as if it was sitting in the car
for braking AS WELL as accelerating the car.

if you dont believe me..... go look up translational to rotational equivalences for Inertia. very straight forward, and often unknown, misunderstood!

mark kibort

Dave did I stump you? you probably forgot the equations, so ill remind you.

if the rim was solid and uniform. (equal weight from inner to outer) you could say the inertia of the rim was calcualated by using this equation:

Inertia = 1/2mr^2

if you are talking just the outer ring area of a wheel. (and I just measured my 3 piece kinesis rims , the two outer pieces ) and if that weight was less than the center portion, which is usually is, then the formula for the inertial mass of the center area only is I=1/2mr^2. BUT, if the mass on the outer is actually going up , then the equation is I =mr^2.

in my " 1.4x of the weight of the wheel equaling what would have to be in the car", equivalence, I assumed that the weight came off the wheel as if it was a "disc". but, since we all know that most of the wheel weight and mass is in the center, the value would actually be lower.

if you want more proof, you can look at the tire and calculate why that value would be 2x the weight as if it was sitting in the car. its obvious when you look at what is really happening. the weight (mass) at the tire, moves at the same speed linearly as the car would be traveling, but faster because centripetal path it takes. so, with a tire , if the weight was all added at the tread, the effect of the intertia (rotational) would have the same effect as 2x the weight as if it was sitting in the car (translational ). but since we are discussing rims, its much less.

upstate bob

I like them. Better than the usual trash you see on an Escalade. Satin works better than the shiny surface. -but then I like phone dials.

vetter59

Nicole said she wanted them so I gave her contact info - I thought very reasonable for $350.

mark kibort

What about those wheels that brian bought for cheap (10s front and rear) they were cheap and i thought looked great i want to say $500 for the set, no?